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Oracle 1z1-809 Certification Exam consists of 85 multiple-choice questions that need to be completed in 150 minutes. 1z1-809 exam covers various topics such as Java Class Design, Generics and Collections, Lambda Built-in Functional Interfaces, Java Stream API, Exceptions and Assertions, Java I/O Fundamentals, Java Concurrency, JDBC, Localization, Annotations, and Java Date/Time API. To pass the exam, you need to score at least 65% of the total marks. By passing the Java SE 8 Programmer II certification exam, you become a certified Java programmer and gain expertise in advanced Java programming concepts.
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Oracle Java SE 8 Programmer II Sample Questions (Q195-Q200):
NEW QUESTION # 195
Given the code fragment:
Stream<Path> files =
Files.walk(Paths.get(System.getProperty("user.home")));
files.forEach (fName -> {//line n1
try {
Path aPath = fName.toAbsolutePath();//line n2
System.out.println(fName + ":"
+ Files.readAttributes(aPath, Basic.File.Attributes.class).creationTime ());
} catch (IOException ex) {
ex.printStackTrace();
});
What is the result?
- A. All files and directories under the home directory are listed along with their attributes.
- B. A compilation error occurs at line n2.
- C. The files in the home directory are listed along with their attributes.
- D. A compilation error occurs at line n1.
Answer: A
NEW QUESTION # 196
Given the code fragment:
What is the result?
- A. 0
- B. A compilation error occurs at line n2.
- C. 1
- D. A compilation error occurs at line n1.
Answer: A
NEW QUESTION # 197
Given the code fragment:
List<String> empDetails = Arrays.asList("100, Robin, HR",
"200, Mary, AdminServices",
"101, Peter, HR");
empDetails.stream()
.filter(s-> s.contains("1"))
.sorted()
.forEach(System.out::println); //line n1
What is the result?
- A. 100, Robin, HR 101, Peter, HR 200, Mary, AdminServices
- B. 100, Robin, HR 200, Mary, AdminServices 101, Peter, HR
- C. E. A compilation error occurs at line n1.
- D. 100, Robin, HR 101, Peter, HR
Answer: A
NEW QUESTION # 198
Given:
public class Emp {
String fName;
String lName;
public Emp (String fn, String ln) {
fName = fn;
lName = ln;
}
public String getfName() { return fName; }
public String getlName() { return lName; }
}
and the code fragment:
List<Emp> emp = Arrays.asList (
new Emp ("John", "Smith"),
new Emp ("Peter", "Sam"),
new Emp ("Thomas", "Wale"));
emp.stream()
//line n1
.collect(Collectors.toList());
Which code fragment, when inserted at line n1, sorts the employees list in descending order of fName and then ascending order of lName?
- A. .sorted (Comparator.comparing(Emp::getfName).thenComparing(Emp::getlName))
- B. .map(Emp::getfName).sorted(Comparator.reserveOrder())
- C. .map(Emp::getfName).sorted(Comparator.reserveOrder().map(Emp::getlName).reserved
- D. .sorted (Comparator.comparing(Emp::getfName).reserved().thenComparing(Emp::getlName))
Answer: D
NEW QUESTION # 199
Given the code fragment:
What is the result?
- A. Javacourse
- B. A compilation error occurs at line n2.
- C. courseJava
- D. A compilation error occurs at line n1.
Answer: B
NEW QUESTION # 200
......
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